hmmmm.....hab es jetzt mal umgeändert von
$this->bbcode_second_pass_code('', 'case "finish": $sql = "INSERT INTO bannerklick (image,bannerurl,dp,geld,reload) VALUES ('".$_POST[image]."','".$_POST[url]."','".$_POST[dp]."','".$_POST[geld]."','".$_POST[reload]."')"; $result = db_query($sql) or die(db_error(LINK)); $row=db_fetch_assoc($result); $tabelle=$row[bannerid];
db_query("ALTER TABLE accounts ADD '$tabelle' UNSIGNED NOT NULL"); ')
in: $this->bbcode_second_pass_code('', 'case "finish": $sql = "INSERT INTO bannerklick (image,bannerurl,dp,geld,reload) VALUES ('".$_POST[image]."','".$_POST[url]."','".$_POST[dp]."','".$_POST[geld]."','".$_POST[reload]."')"; $result = db_query($sql) or die(db_error(LINK));
$sql = "SELECT * FROM bannerklick WHERE bannerurl = '$_POST[URL]'"; $result = db_query($sql) or die(db_error(LINK)); $row=db_fetch_assoc($result); $tabelle=bannerklick.$row[bannerid];
db_query("ALTER TABLE accounts ADD '$tabelle' UNSIGNED NOT NULL"); ')
aber er bringt nun diese fehlermeldung:
$this->bbcode_second_pass_code('', 'ALTER TABLE accounts ADD 'bannerklick' UNSIGNED NOT NULL You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''bannerklick' UNSIGNED NOT NULL' at line 1')
hmmm... das ist die tabelle.... $this->bbcode_second_pass_code('', 'CREATE TABLE `bannerklick` ( `bannerid` int(11) unsigned NOT NULL auto_increment, `image` varchar(250) NOT NULL default 'http://', `bannerurl` varchar(225) NOT NULL default 'http://', `dp` int(3) NOT NULL default '0', `geld` int(3) NOT NULL default '0', `aktiv` tinyint(4) NOT NULL default '0', `reload` int(4) NOT NULL default '0', `klicks` int(9) NOT NULL default '0', PRIMARY KEY (`bannerid`) );')
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